A block of mass m 1 is kept over another block of mass m 2 and the system rests on a horizontal
surface (as shown in figure). A constant horizontal force 2F acting on the lower block produces an acceleration 
in the system, the two blocks always move together.
Text Solution
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Solution:
a = 
f 1 = m 1 a = m 1 
2F – f 1 – f 2 = m 2 a
– f 2 = – 2F + f 1 + m 2 a = m 1 a + m 2 a – 2F
– f 2 = (m 2 + m 1 ) 
– 2F = F – 2F = – F ⇒ f 2 = – F
2F – µ K (m 2 + m 1 ) g = (m 2 + m 1 ) a
2F – (m 2 + m 1 ) 
= µ K (m 2 + m 1 ) g ⇒ 
= µ K
W = work done by friction force on smaller block
= f 1 x = 
x
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