A uniform ring of radius R is given a back spin of angular velocity V 0 /2R and thrown on a horizontal rough surface with velocity of center to be V 0 . The velocity of the centre of the ring when it starts pure rolling will be
Text Solution
Verified by ExpertsThe correct answer is:
B
Here, u = V 0 , ω 0 = 
At pure rolling ;
V = V 0 – 
t
& 
= 
t (In pure rolling V = R ω ) ( V = R ω )( α = 
= 
)
⇒ V 0 – V = V + 
⇒ 2V = 
⇒ V = 
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