In a neutral conducting hollow sphere of inner and outer radii 5 cm and 10 cm respectively, a point charge Q = 1 C is placed at point A, that is 3 cm from the center C of the hollow sphere. An external uniform electric field of magnitude 20 N/C is also applied. Net electric force on this charge is 15 N, away from the center of the sphere as shown. Then find:
Text Solution
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20 N right hand side
35 N right hand side
35 N left hand side
Sol. The net force on point charge Q at A is zero in the cavity due to external electric field and external induced charges on body of conductor.
Hence force on point Q due to induced charges is 35 N towards left.
By action reaction principle, force on sphere due to point charge Q is 35 N rightward.
F 1 = Force on Q due to induced charge on S 1 = 15 N,
F 1 ' = Force on S 1 due to Q = 15 N
F 2 = Force on Q due to induced charge on S 2 = 20 N
F 2 ' = Force on S 2 due to Q = 20 N
F 3 = Force on Q due to electric field E
F 1 , F 1 ' and F 2 , F 2 ' are action reaction force.
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