In the situation shown in figure, for what value of minimum horizontal force F (in Newton), sliding between middle and lower block will start? (Take g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(30 N)
Sol. for uppermost block a max. = 1 m/s 2
for lowermost block a max = 
= 2 m/s 2
Hence sliding between middle and lower block will start only after sliding between middle and upper
block has already started.
for middle block F – 18 = 6 × 2
F = 30 N
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A body of mass 5 kg is kept on a rough horizontal surface. It is found that the body does not slide…
In the given figures find the accelerations and the friction forces involved
(i)
(ii)
(iii)
(iv)
In the given figure find the accelerations of blocks A and B for the following cases (g = 10 m/s 2 …
Column II gives certain situations involving two blocks of mass 2 kg and 4 kg. The 4 kg block lies …
In the arrangement shown tension in the string connecting 4kg and 6kg masses is
In the given figure the coefficient of friction between 4kg and 5 kg blocks is 0.2 and between 5 kg…