In a Young's double slit experiment, d = 1 mm, λ = 6000 Å & D = 1 m. The slits produce same intensity on the screen. The minimum distance between two points on the screen having 75 % intensity of the maximum intensity is
Text Solution
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Lets look at the screen.
As we know that 75% intensity will correspond to a point where intensity is 3 Ι 0 .
{ I max = 4 I 0 }
I = I 0 + I 0 + 
cos (Δφ)
3 I 0 = 2 I 0 (1 + cos Δφ )
cos ( Δφ ) =
Δφ = 
, 2 π – 
, 2 π + 
,...........
Δ p = 
, λ – 
, λ + 
,...........
Δ p = 
= 
⇒ y = 
× 
,........
y = 
, β – 
, β + 
y min. = 
y = 
× 
= 
= 0.2 mm
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