In a young's double slit experiment 
and 
. Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity:
A
B
C
D
125 m
Text Solution
Verified by ExpertsThe correct answer is:
B
[Intensity is half of the maximum]
Minimum distance from central maximum corresponding to 
is
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
What is the effect on the fringe width of interference fringes in a Young's double slit experiment …
Two slits separated by a distance of 1 mm, are illuminated with red light of wavelength 6.5 × 10 –7…
In a Young’s double slit experiment, the fringe width is found to be 0.4 mm. If the whole apparatus…
Find the angular fringe width in a Young’s double slits experiment with blue-green light of wavelen…
A source emitting two light waves of wavelengths 580 nm and 700 nm is used in a young's double slit…
A flint glass and a crown glass are fitted on the two slits of a double slit apparatus. The thickne…