In youngs double slit experiment, distance between the slits is d and that between the slits and screen is D. Angle between principle axis of lens and perpendicular bisector of S 1 and S 2 is 45°. The point source S is placed at the focus of lens and aperture of lens is much larger than d. Assuming only the reflected light from plane mirror M is incident on slits, distance of central maxima from O will be :

Text Solution
Verified by ExpertsThe correct answer is:
A
From the figure shown below it is clear that the distance of central maxima from O is D.

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
What is the effect on the fringe width of interference fringes in a Young's double slit experiment …
Two slits separated by a distance of 1 mm, are illuminated with red light of wavelength 6.5 × 10 –7…
In a Young’s double slit experiment, the fringe width is found to be 0.4 mm. If the whole apparatus…
Find the angular fringe width in a Young’s double slits experiment with blue-green light of wavelen…
A source emitting two light waves of wavelengths 580 nm and 700 nm is used in a young's double slit…
A flint glass and a crown glass are fitted on the two slits of a double slit apparatus. The thickne…